7x^2-67x-108=0

Solution for 7x^2-67x-108=0 equation:

7x^2-67x-108=0

a = 7; b = -67; c = -108;
Δ = b2-4ac
Δ = -672-4·7·(-108)
Δ = 7513
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-67)-\sqrt{7513}}{2*7}=\frac{67-\sqrt{7513}}{14}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-67)+\sqrt{7513}}{2*7}=\frac{67+\sqrt{7513}}{14}
$